1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
Answer: D )
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
Answer: C )
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >, yes.
For this question you can say:
154/11 = 252/?
so ? is the hours she would work:
252*11/154 = 18 hours :)))
i hope this is helpful
have a nice day
Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
Answer:
Volume is 
Solution:
As per the question:
Diameter, d = 40 m
Radius, r = 20 m
Now,
From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:
iff
h(y) = cy + d
Then
when y = 1 m
h(- 20) = 1 m
1 = c.(- 20) + d = - 20c + d (1)
when y = 9 m
h(20) = 9 m
9 = c.20 + d = 20c + d (2)
Adding eqn (1) and (2)
d = 5 m
Using d = 5 in eqn (2), we get:
Therefore,
Now, the Volume of the pool is given by:
where
A = 
Thus
![V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}](https://tex.z-dn.net/?f=V%20%3D%20%5B-%20533.33cos%5Ctheta%20%2B%201000%5Ctheta%5D_%7B0%7D%5E%7B2%5Cpi%7D)
7/8+(−2/3) divided by 5/6
(7/8 - 2/3)/(5/6)
=(21/24 - 16/24) / (5/6)
= (5/24) / (5/6)
= 5/24 * 6/5
= 6/24
= 1/4
