Find the equations of the lines...
First find the slope...(y2-y1)/(x2-x1)=m
m=(6-1)/(8-5)=5/3 and it passes through (5,1) so
y=mx+b becomes:
y=5x/3+b and using (5,1)
1=5(5)/3+b
1=25/3+b
3/3-25/3=b
b=-22/3 so
y1=(5x-22)/3
.... now y2...
m=(8-3)/(-1--4)=5/3 (note it has the same slope as y1...
y=5x/3+b and using the point (-1,8)
8=5(-1)/3+b
8=-5/3+b
24/3+5/3=b
b=29/3, now note that the y-intercept is different...
y2=(5x+29)/3
Since these lines have the same slope but different y-intercepts, they are parallel to each other. (and will never intersect.)
Answer:
The answer is c and b
Step-by-step explanation:
I took the test
Answer:
b is the answer
Step-by-step explanation:
Given:
The arithmetic sequence is −15, −33, −51, −69.
To find:
The nth term of the arithmetic sequence.
Solution:
We have,
−15, −33, −51, −69
Here,
First term: a = -15
Common difference is
Now, nth term of an arithmetic sequence is
Substitute a=-15 and d=-18.
Therefore, the nth term of the given arithmetic sequence is .
Answer:
36 students
Step-by-step explanation:
because if 1/6 is 6 students then you have to multiply the 6 by 6
