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Dima020 [189]
3 years ago
6

Which of these properties is a general property common to both acidic and basic solutions?

Chemistry
2 answers:
Len [333]3 years ago
8 0
Conducts electricity 
PSYCHO15rus [73]3 years ago
4 0

Answer: Conducts electricity

Explanation:

Acids are substances which donates H^+ ions in solution.

HCl\rightarrow H^++Cl^-

Acids are sour in taste, react with metals and conduct electricity due to the production of ions which helps in the transfer of electrons.

Bases Acids are substances which donates OH^- ions in solution.

NaOH\rightarrow Na^++OH^-

Bases are bitter in taste, react with non metals and conduct electricity due to the production of ions which helps in the transfer of electrons.

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How many milliliters of a 25% (m/v) NaOH solution would contain 75 g of NaOH?
Luda [366]

Answer:

E  3.0 x 10² mL.

Explanation:

Hello there!

In this case, according to the formula for the calculation of the mass-volume percent:

\% m/V=\frac{m_{solute}}{V_{solution}}*100\%

Whereas it is necessary to know the mass of the solute and the volume of the solution. Thus, given the mass of NaOH as the solute, the volume of the solution would be:

V_{solution}=\frac{m_{solute}}{\% m/V}*100\%

Then, by plugging in we obtain:

V_{solution}=\frac{75g}{25\%}*100\%\\\\V_{solution}=3.0x10^2mL

Thus, the answer is E  3.0 x 10² mL.

Best regards!

5 0
3 years ago
The unit for energy is the___
Bas_tet [7]
A joule is the unit for energy
8 0
4 years ago
HELP ME !!
lorasvet [3.4K]

Answer:

Yes

Explanation:

AsH3 contains a polar bond.

3 0
4 years ago
A certain substance X has a normal freezing point of −3.1°C and a molal freezing point depression constant =Kf·6.23°C·kgmol−1. C
muminat

Answer:

Freezing T° of solution =  - 7.35 °C

Explanation:

This is about the freezing point depression, a colligative property which depends on solute.

The formula is: Freezing T° pure solvent - Freezing T° solution = m . Kf . i

Freezing T° of pure solvent is -3.1°C

At this case, i = 1. As an organic compound the urea does not ionize.

We determine the molality (mol/kg of solvent)

We convert mass to moles:

12.3 g . 1mol / 60.06 g = 0.205 moles

0.205 mol / 0.3 kg = 0.682 mol/kg

We replace data in the formula:

-3.1°C - Freezing T° of solution  = 0.682 mol/kg . 6.23 kg°C/mol . 1

Freezing T° of solution = 0.682 mol/kg . 6.23 kg°C/mol . 1 + 3.1°C

Freezing T° of solution =  - 7.35 °C

6 0
4 years ago
Calculate the volume, in liters, occupied by 1.80 moles of H2 gas at STP.
masha68 [24]

Answer:

40.32L

Explanation:

So we know that 22.4 Liters is one mole of a gass so we can set up an equation to test that

1mole     1.8mole

_____ = _____

22.4L         x

and then cross multiply so you get 40.32L

3 0
3 years ago
Read 2 more answers
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