40 g NaOH. You must use 40 g NaOH to prepare 10.0 L of a solution that has a pH of 13.
<em>Step 1</em>. Calculate the pOH of the solution
pOH = 14.00 – pH = 14.00 -13 = 1
<em>Step 2</em>. Calculate the concentration of NaOH
[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-1) mol/L = 0.1 mol/L
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 10.0 L solution × (0.1 mol NaOH/1 L solution) = 1 mol NaOH
<em>Step 4</em>. Calculate the mass of NaOH
Mass of NaOH = 1 mol NaOH × (40.00 g NaOH/1 mol NaOH) = 40 g NaOH
Answer:
This is an example of a food chain
Explanation:
Think of it as a chain reaction. The grass feeds and nourishes the prairie dog. Upon eating the prairie dog, the coyote gets the nutrients from both the grass the prairie dog ate and from the prairie dog itself.
Answer:
Volume occupied by 10 grams of Lithium Oxide at STP is 7.52 L
Explanation:
STP (Standard Temperature and Pressure) : It is used while performing calculation on gases and provide standards of measurements while performing experiment.
According to IUPAC (International Union of Pure And applied Chemistry) , standard temperature is 273.15 K and Pressure is 100 kPa (0.9869 atm). At STP condition 1 mole of substance occupies 22.4 L volume .
Molar mass of Lithium Oxide = 29.8 g/mol
= 2(6.9) + 15.99 = 29.8
Mass of 1 mole = 29.8 g
1 mole occupies, Volume = 22.4 L
29.8 g occupies, V = 22.4 L
1 g occupies ,V =
1 g occupies ,V = 0.7516 L
10 g tex]Li_{2}O[/tex] occupies ,V = L
V = 7.52 L
So, volume occupied by Lithium Oxide At STP is 7.52 L
Answer:
The object at 50°C will have a higher kinetic energy.
Explanation:
Temperature is a measure of the average kinetic energy of the particles in an object. As you introduce more energy into the system (e.g. heat the object), the particles on average move faster because they have more kinetic energy.
SUBTRACTION.
explanation: PEMDAS, The last one is subtraction