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soldier1979 [14.2K]
3 years ago
12

How many atoms are needed to react with 50 grams of O2 gas

Chemistry
1 answer:
natita [175]3 years ago
4 0

Answer:

3 moles

Explanation:

3 moles atoms are needed to react with 50 grams of O2 gas.

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The compound Xe(CF3)2 decomposes in afirst-order reaction to elemental Xe with a half-life of 30. min.If you place 7.50 mg of Xe
Irina-Kira [14]

Answer:

t=147.24\ min

Explanation:

Given that:

Half life = 30 min

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30}\ min^{-1}

The rate constant, k = 0.0231 min⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.0231 min⁻¹

Initial concentration [A_0] = 7.50 mg

Final concentration [A_t] = 0.25 mg

Time = ?

Applying in the above equation, we get that:-

0.25=7.50e^{-0.0231\times t}

750e^{-0.0231t}=25

750e^{-0.0231t}=25

x=\frac{\ln \left(30\right)}{0.0231}

t=147.24\ min

6 0
3 years ago
Which statement describes J.J. Thomson’s plum-pudding model of the atom?
ra1l [238]
Option C: the electrons are embedded in a positive sphere.

As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.
4 0
3 years ago
Balancing equations<br> I'll give brainliest.
wel

Answer:

You should follow these steps:

Count each type of atom in reactants and products.

Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

Repeat steps 1 and 2 until the equation is balanced.

Explanation:

7 0
2 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
3 years ago
Which two factors are most likely to cause a plants guard cell to open its stomata
Elanso [62]

Explanation:

Water Content of Epidermal Cells

Temperature: Increase in the temperature causes stomata to open

4 0
3 years ago
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