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Over [174]
2 years ago
8

Can anyone help me with this math question please I will give brainlist!!

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
5 0

Answer:

it's (4,4) since the point is right on top of (4,6) and by doing that it would make a closed quadrilateral

Step-by-step explanation:

it would be best to plot your points and whichever it lands on would be your next point.

DochEvi [55]2 years ago
5 0

Answer:

Option b

As it 4,4 lines in quadrilateral of 4,6

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Answer:

sim eu também preciso desta respota

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3 years ago
decompose the mixed number 2 4/5
ratelena [41]

Answer:

2 \frac{4}{5}

\frac{2 \times 5 + 4}{5}

\frac{14}{5}

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7 0
2 years ago
A chess board is an 8 by 8 grid of squares. If you randomly choose 3 squares on the board, what is the probability that:
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2 years ago
Laura bought a square canvas to paint a picture of her cat one side measured 22 centimeters what is tha area of the canvas
Olin [163]
Hi there!

To start, squares are a shape in which all of its sides are congruent to one another. Knowing the length of one side would mean that you would know the length of all the other sides. 

Because you know that one side measures 22 cm, you can conclude that all the other sides of the square are also at a length/width of 22 cm.

Next, you will find the area of the square. 

Because the area formula is Area=Length * Width, you can easily find the area of the square by multiplying 22*22 since the length and width of any square is the same.

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8 0
3 years ago
xP(x)00.2510.0520.1530.55Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal pl
Nookie1986 [14]

The Solution:

Given:

Required:

Find the standard deviation of the probability distribution.

Step 1:

Find the expected value of the probability distribution.

E(x)=\mu=\sum_{i\mathop{=}0}^3x_iP_(x_i)\begin{gathered} \mu=(0\times0.25)+(1\times0.05)+(2\times0.15)+(3\times0.55) \\  \\ \mu=0+0.05+0.30+1.65=2.0 \end{gathered}

Step 2:

Find the standard deviation.

Standard\text{ Deviation}=\sqrt{\sum_{i\mathop{=}0}^3(x_i-\mu)^2P_(x_i)}=(0-2)^2(0.25)+(1-2)^2(0.05)+(2-2)^2(0.15)+(3-2)^2(0.55)=4(0.25)+1(0.05)+0(0.15)+1(0.55)=1+0.05+0+0.55=1.60

Thus, the standard deviation is 1.60

Answer:

1.60

8 0
1 year ago
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