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3 years ago

What do the outliers mean

Mathematics

1 answer:

irakobra [83]3 years ago

6 0

A person or thing situated away or detached from the main body or system

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How is the measure of an arc related to its central angle?

KATRIN_1 [288]

Answer:

Arc Measure: In a circle, the degree measure of an arc is equal to the measure of the central angle that intercepts the arc. Arc Length: In a circle, the length of an arc is a portion of the circumference. The letter "s" is used to represent arc length.

Step-by-step explanation:

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3 years ago

If f(x)=x^2+9x and g(x)=1/x, find f(g(-1)).

shtirl [24]

Answer:

x=3

Step-by-step explanation:

x^2-9

bcos g(-1)=-1

f(g)=x^2+9(-1)=0

x^2-9=0

x^2=9

x=√9

x=3

8 0

3 years ago

Read 2 more answers

what's the slope? simplify your answer and write it as a proper fraction,improper fraction or integer

dybincka [34]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

In this graph, when you count rise and run, rise would be 1 and run would be 2. Because slope is also known as rate of change and rate of change is also known as rise over run, the slope will be 1 over 2.

8 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :