<u>Answer:</u>
(0.5, -0.5)
<u>Step-by-step explanation:</u>
We are given a line segment on the graph with two known points (ending points) and we are to find its mid point.
We know the formula for the mid point:
Substituting the coordinates of the given points in the above formula:
Mid point = 
= (0.5, -0.5)
9514 1404 393
Answer:
B. 3x^2 +11x -20 = 0
Step-by-step explanation:
For solutions p and q, the quadratic will be
(x -p)(x -q) = 0
We notice that the leading coefficients of the offered answer choices are greater than 1, so it will be convenient to use a value that "clears fractions."
(x -4/3)(x -(-5)) = 0
3(x -4/3)(x +5) = 0 . . . . multiply by 3 to clear the fraction
(3x -4)(x +5) = 0 . . . . . . clear the fraction
3x(x +5) -4(x +5) = 0 . . use the distributive property
3x^2 +15x -4x -20 = 0 . . . . use the distributive property again
3x^2 +11x -20 = 0 . . . . collect terms
_____
The constant in the product of factors is the product of roots:
(x -p)(x -q) = x^2 -(p+q)x +pq
Here, that would mean the constant would be (4/3)(-5) = -20/3.
If we compare the above quadratic to the standard form:
ax^2 +bx +c = 0
we find that we can divide the standard form equation by 'a' to get ...
pq = c/a
That is, c/a = -20/3, so we might start looking for an answer choice that has a leading coefficient of a=3 and a constant of c=-20.
Lets write down what we know...
Laura walks 3/5 mile to school everyday
Laura=3/5mile
Isaiah's walk is 3 times as long as Lauras, so
Isaiah=Laura*3
We know how far Lauras walk is so we can solve for Isaiah's walk
Isaiah=3/5*3 (or Isaiah=3/5+3/5+3/5 if thats easier for you to solve for)
Isaiah=9/5 miles
Now we know the answer! Great, Isaiah walks 9/5 miles to school each day. But 9/5 is an improper fraction, so lets convert it to a mixed number.
9/5=
To solve for this, we have to find out how many times 5 can go into 9. 5 goes into 9 one time with a remainder of 4, so we can write the mixed number as.
9/5= 1 4/5
Isaiah walks 9/5miles or 1 4/5 miles. Both are correct.
Answer:
B. Period 1 had scores that were less spread out around the mean than
Period 2
Step-by-step explanation:
Because the standard deviation of Period 2's scores is greater than that of Period 1's, the test scores for Period 2 are going to be more spread out than Period 1's test scores. B is the most logical choice in this case.
Answer:
7
Step-by-step explanation:
