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3 years ago

What is the answer to 16x8

Mathematics

2 answers:

kati45 [8]3 years ago

8 0

128
Explanation

6*8 = 48
Carry the 4
8*1 =8+4 gives u 12
128 is your answer

Karolina [17]3 years ago

6 0

Answer is: 16x8 = 128

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Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

Explanation:-

Given data

Brown Blue Hazel Green

Females 13 4 6 9

Males 10 2 9 12

Let 'B' be the event of brown eyes

Total number of males n(M) = 33

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$

From table the brown eyes from males = 10

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

Final answer:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

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3 years ago

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Afina-wow [57]

Solution B is the one she should use

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3 years ago

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3 years ago

16/__ = -8 ___/12 = -6

Karolina [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

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3 years ago