Factor out the GCF of
21
b
2
c
2
from
63
b
2
c
4
+
42
b
3
c
2
.
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Factor out the GCF of
21
b
2
c
2
from each term in the polynomial.
Tap for fewer steps...
Factor out the GCF of
21
b
2
c
2
from the expression
63
b
2
c
4
.
21
b
2
c
2
(
3
c
2
)
+
42
b
3
c
2
Factor out the GCF of
21
b
2
c
2
from the expression
42
b
3
c
2
.
21
b
2
c
2
(
3
c
2
)
+
21
b
2
c
2
(
2
b
)
Since all the terms share a common factor of
21
b
2
c
2
, it can be factored out of each term.
21
b
2
c
2
(
3
c
2
+
2
b
)
The greatest common factor
GCF
is the term in front of the factored expression.
21
b
2
c
2
Step-by-step explanation:
![\frac{y_2-y_1}{x_2-x_1}=\frac{15-(-13)}{28-(-28)}\\=\frac{28}{2(28)}\\\therefore\ m=\frac{1}{2}\\\frac{y-y_1}{xl-x_1}=m]\\\frac{y+13}{x+28}=\frac{1}{2}\\2y+26=x+28\\2y=x+2\\ y=\frac{1}{2}x+1](https://tex.z-dn.net/?f=%20%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%3D%5Cfrac%7B15-%28-13%29%7D%7B28-%28-28%29%7D%5C%5C%3D%5Cfrac%7B28%7D%7B2%2828%29%7D%5C%5C%5Ctherefore%5C%20m%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5Cfrac%7By-y_1%7D%7Bxl-x_1%7D%3Dm%5D%5C%5C%5Cfrac%7By%2B13%7D%7Bx%2B28%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C2y%2B26%3Dx%2B28%5C%5C2y%3Dx%2B2%5C%5C%20y%3D%5Cfrac%7B1%7D%7B2%7Dx%2B1)
In order to find y for point C on AB, substitute point C in line equation if AB.
The answer to this math problem is 110 km/h
