Question

Lebron wants to put a fence around a community garden plot. The plot is a rectangular shape with a length twice as long as its width. If the plot has an area of 200 feet squared (200ft2), how many feet of fencing will Lebron need?

Answer 1

Answer:

60 feet of fencing

Step-by-step explanation:

Let x feet be the width of the garden plot, then 2x feet is the length of  the garden plot.

The area of the garden plot is

$A=x\cdot 2x\\ \\200=2x^2\\ \\100=x^2\\ \\x=10\ feet\\ \\2x=20\ feet$

Find the perimeter of the rectangular garden plot:

$P=x+2x+x+2x\\ \\=10+20+10+20\\ \\=60\ feet$

Answer 2

Answer:

The length of the fence that Lebron requires is:

• 60 feet.

Step-by-step explanation:

Since the land is mentioned to be rectangular twice as long as it is wide, it must be calculated taking into account the given area of ​​200 square feet, which can be done using the following formula:

• Area = Width (W) * Length (L)

The formula is replaced based on a single variable:

• 200 sq. ft = W * 2W (Since it is mentioned that the length is twice the width).

Performing the multiplication we obtain:

• 200 sq. ft = 2W ^ 2

Pass the number you are multiplying to divide on the other side of equality:

• 200 sq. ft / 2 = W ^ 2

To eliminate the square, the square root is taken from both sides of the equality:

• root (200 sq. ft / 2) = W
• W = root (200 sq. Ft / 2)
• W = 10 feet

Since the length is twice the width then:

• L = W * 2 = 10 * 2 = 20 feet

Having the dimensions, the Perimeter can be calculated, which is the length that surrounds the terrain, which is calculated for rectangles such as:

• Ground perimeter = 2 * width + 2 * length.

By replacing you get:

• Ground perimeter = 2 * 10 feet + 2 * 20 feet.
• Ground perimeter = 20 feet + 40 feet.
• Ground perimeter = 60 feet.