Answer:
6. D.
7. F.
8. A.
9. B.
10. C.
Step-by-step explanation:
6. 9 + (12 - 10)
12 - 10 = 2
9 + 2 = 11
7. (20 - 15) x 2
20 - 15 = 5
5 x 2 = 10
8. 10 ÷ 5 + 7
10 ÷ 5 = 2
2 + 7 = 9
9. 6 + 2 x 3
2 x 3 = 6
6 + 6 = 12
10. (2 x 4) + 8
2 x 4 = 8
8 + 8 = 16
Let me know if this helps!
Answer:
x² + 6x - 27 = 0
x² + 9x - 3x - 27 = 0
x ( x + 9 ) - 3 ( x + 9 ) = 0
( x + 9 ) ( x - 3 ) = 0
Thus ,
x = -9 or x = 3
I hope it helps you
#Indian : )
Answer: B. 1.85 + x = 5.30
Explanation:
The starting height of the tree was 1.85 meters. To find the number of meters the tree grew, you would subtract the current height from the previous height.
5.30-1.85=x. This equation is the same as 1.85 + x = 5.30 if you switch the 5.30 and x.
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]
Answer:
25
Step-by-step explanation:
Given the function that represents the amount of mosquitoes as;
M(x) = -(x-5)² + 25
To get the maximum mosquitoes possible, we need to first find x;
At the maximum dM/dx = 0
dM//dx = -2(x-5)
0 = -2(x-5)
-2(x-5) = 0
-2x + 10 = 0
-2x = -10
x = 10/2
x = 5
Substitute x = 5 into the function;
M(5) = −(5−5)² +25
M(5) = 0+25
M(5) = 25
Hence the maximum number of mosquitoes is 25
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.
