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2 years ago

Which is greater, 76% or 0.67?

Mathematics

1 answer:

yulyashka [42]2 years ago

3 0

Answer:

76%

Step-by-step explanation:

76% is 0.76

So it's is greater than 0.67

76%>0.67

You might be interested in

The weights of professional wrestlers are approximately normally distributed with a mean of 220 pounds and a standard deviation

nikdorinn [45]

Answer:

1.6%

Step-by-step explanation:

The cumulative distribution function (CDF) of a random variable X is denoted by F(x), and is defined as

F(x) = P(X ≤ x). where x is the largest possible value of X that is less than or equal to x

z = (x-μ)/σ,

where:

x is the raw score = 205

μ is the population mean, = 220 pounds

σ is the population standard deviation = 7 pounds

205 -220/7

z = -15/7

z = -2.1428571429

Using the normal cdf function on your graphing calculator,the cumulative distribution is

normalcdf( -2.1428571429, 100)

= 0.01606229

In percent form = 0.01606229 × 100

= 1.6%

5 0

2 years ago

Kevin wants to buy 2.5 pounds of chicken at $6.49 per pound. How <br> much will he pay?

pochemuha

Answer:

16.225

just times 2.5 times 6.49

6 0

3 years ago

Which algebraic expression represents "the bagels were divided equally into fifteen bags"? 15 + b 157b StartFraction 15 Over b E

maria [59]

Answer: (d)- $\dfrac{b}{15}$

Step-by-step explanation:

Suppose 'b' is the number of bagels

It is to be divided into 15 bags

So, we use the divide operator i.e.

$\Rightarrow b\ \div\ \15=\dfrac{b}{15}$

5 0

3 years ago

Read 2 more answers

7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th

vampirchik [111]

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

μ = np = 9.72

$\sigma = \sqrt{np(1-p)}$

$=\sqrt{8.8452}$

= 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

$=P(-0.75 < z < -0.41)$

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

$=P(0.60 < z < 0.94)$

Using z table,

= P(z< 0.94)-P(z< 0.60)

= 0.8294 - 0.7257

= 0.1006

7 0

3 years ago

Please help need a 100

aivan3 [116]

I'd have to say it's A. Please don't blame me if I'm wrong. :)

4 0

3 years ago