<span>10 < –2b or 2b + 3 > 11 represents 2 different sets of numbers.
</span><span>10 < –2b can be reduced by dividing both sides by -2; you must then reverse the direction of the < sign: -5 > b, which is the interval b < -5: (-infinity, -5).
</span>2b + 3 > 11 reduces to 2b > 8, which in turn reduces to b > 4: (4, infinity).
It may be helpful to graph these sets.
If you really do mean "<span>10 < –2b or 2b + 3 > 11," then the "solution" is made up of two sub-intervals: b < -5 and b > 4.
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Answer:
96-28 68
Step-by-step explanation:
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❖ T (8, 2) reflected across the x-axis is (8, -2). When you reflect over the x-axis, the sign in front of the y coordinate changes. When you reflect over the y-axis, the sign in front of the x coordinate changes.
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Which point could be removed in order to make the relation a function? (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}
stepan [7]
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
<em>Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.</em>
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
<h3>So, we need to remove any one (0, –2) or (0, 8) to make the relation a function.</h3>
<span>Yes it is true that a continuous function that is never zero on an interval never changes sign on that interval. This is because of ever important Intermediate Value Theorem.</span>
