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Elodia [21]
3 years ago
11

How to factor: 6x^5-11x^4-10x^3-54x^3+99x^2+90x

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0
6x^5 - 11x^4 - 10x³ - 54x³ + 99x² + 90x

6x^5 - 11x^4 + (-10x³ - 54x³) + 99x² + 90x      collect like terms

6x^5 - 11x^4 - 64x³ + 99x² + 90x            simplify

hope this helps, God bless!
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Emma has money into savings accounts. One rate is 8% and the other is 12%. If she has $450 more in the 12% account and the total
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Let's say that the value invested in the account with a rate of 8% is "x", then the amount invested in the account with a rate of 12% is:

x+450

To calculate the total interest we need to calculate the interest of each individual account and sum them:

\begin{gathered} \frac{8}{100}\cdot x=0.08\cdot x \\ \frac{12}{100}\cdot(x+450)=0.12\cdot x+54 \end{gathered}

The total interest is the sum of the two expressions above:

\begin{gathered} 220=(0.08\cdot x)+(0.12\cdot x+54) \\ 220=0.08\cdot x+0.12\cdot x+54 \\ 220-54=0.2\cdot x \\ 166=0.2\cdot x \\ 0.2\cdot x=166 \\ x=\frac{166}{0.2} \\ x=830 \end{gathered}

The value invested in the account with 8% interest is 830, the one invested in the account with 12% interest is 1280.

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