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Elodia [21]
3 years ago
11

How to factor: 6x^5-11x^4-10x^3-54x^3+99x^2+90x

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0
6x^5 - 11x^4 - 10x³ - 54x³ + 99x² + 90x

6x^5 - 11x^4 + (-10x³ - 54x³) + 99x² + 90x      collect like terms

6x^5 - 11x^4 - 64x³ + 99x² + 90x            simplify

hope this helps, God bless!
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Consider the system of equations.
Harman [31]

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

The given system of equations:

x  +  2y  =  1............(1)

-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Find the determinant of \left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]

\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle  = 4

\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12

\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8

x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

Learn more here: brainly.com/question/4428059

3 0
2 years ago
Select the correct answer. Which table represents a linear function with a greater y-intercept than that of the function represe
Sladkaya [172]

Answer:

C

Step-by-step explanation:

i just know i guess

5 0
2 years ago
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How much chocolate will each person get if 3 people share 1/2 pound of chocolate equally?
eimsori [14]
1/6 pound of chocolate for each person ( 1/2 / 3 ).
3 0
3 years ago
A tire company finds that the lifespan for one brand of its tires is normally distributed with a mean of 47,500 miles and a stan
Illusion [34]

Answer:

42580 miles

Step-by-step explanation:

Mean = \mu = 47500

\sigma = 3000

The manufacturer does not want to replace more than 5% of the tires

P(X\leq x)=5\%

P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05

By using normal table values :

\frac{x-47500}{3000}=-1.64

x=(-1.64 \times 3000)+47500

x=42580

Hence the approximate number of miles for the warranty is 42580 miles

6 0
3 years ago
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lidiya [134]
Your answer is point g and h

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3 years ago
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