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Anni [7]
3 years ago
12

Factoring Quadratic Expressions: 5p^2 - p - 18

Mathematics
1 answer:
VMariaS [17]3 years ago
7 0
5p² - p - 18 = (5p +9)(p - 2)
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HELP ASAP PLEASE HELP FAST
s344n2d4d5 [400]
The answer would be B, because you would just multiply 116.22 by 500
8 0
4 years ago
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A triangle has a perimeter of 18 inches. If one side has length 8 inches, find the length of the shortest side if the other leng
aalyn [17]
a,b,c-\ sides\ of\ triangle\\\\a+b+c=18\ inches\\\\a=8inch\\\\\frac{b}{c}=\frac{2}{3}\\\\3b=2c\ \ --->b=\frac{2c}{3}\\\\8+\frac{2c}{3}+c=18\ |*3\\\\24+2c+3c=54\\\\5c=54-24\\\\5c=30\\\\c=\frac{30}{5}=6\\\\Length\ of\ shorter\ side\ is\ equal\ to\ 6\ inches.
8 0
3 years ago
The school store sells 4 pencils for $0.50. At this rate, what is the cost in dollars) of 10 pencils?
Pachacha [2.7K]

Answer:

1.25

Step-by-step explanation:

10/4=2.5

2.5*0.5

7 0
3 years ago
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How do I find the vertex and the standard form? Plz explain
xenn [34]

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

y = -4(x^2 + 6x + 9) + 10

y = -4x^2 - 24x -36 + 10

y = -4x^2 -24x -26

7 0
3 years ago
In the given figure, mWY = 76° and mXZ = 112. What is the difference of the measures of angle WPY and angle XPY?
skelet666 [1.2K]

Please consider the attached image for complete question.

We have been given that measure of arc WY is 76° and and measure of arc XZ is 112°. We are asked to find the difference of of the measures of angle WPY and angle XPY.

First of all we will find the measure of angle WPY using intersecting secants theorem. Intersecting secants theorem states that measure of angle formed by two intersecting secants inside a circle is half the sum of intercepting arcs.

m\angle WPY=\frac{1}{2}(\widehat{WY}+\widehat{XZ})

m\angle WPY=\frac{1}{2}(76^{\circ}+112^{\circ})

m\angle WPY=\frac{1}{2}(188^{\circ})

m\angle WPY=94^{\circ}

We can see that angle WPY and angle XPY are linear angles, so they will add up-to 180 degrees.

m\angle WPY+m\angle XPY=180^{\circ}

94^{\circ}+m\angle XPY=180^{\circ}

94^{\circ}-94^{\circ}+m\angle XPY=180^{\circ}-94^{\circ}

m\angle XPY=86^{\circ}

Now we need to find difference of both angles as:

m\angle WPY-m\angle XPY=94^{\circ}-86^{\circ}

m\angle WPY-m\angle XPY=8^{\circ}

Therefore, the difference of the measures of angle WPY and angle XPY is 8 degrees.

6 0
3 years ago
Read 2 more answers
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