The
probability that the student has a part-time job, given that they have a cell phone is 5/8
<h3>What is probability</h3>
Probability is the likelihood or chance that an event will occur.
Given the following parameter:
- Total student = 80%
- Part-time jobs = 45%
- Those with both a cell phone and a part-time job = 30%
Student will cellphone only = 80 - 30 = 50%
The
probability that the student has a part-time job, given that they have a cell phone is 50/80 = 5/8
Learn more on probability here: brainly.com/question/25870256
Answer:
It's an angle bisector
Step-by-step explanation:
It is between 2 congruent angles therefore bisects those angles
Firstly, we can convert all of the fractions into percentages. To do this, we need to make the denominator of the fraction 100, and whatever we do to the denominator we must also do to the numerator.
5 x 20 = 100
1 x 20 = 20.
So Carl recieves 20/100 or 20% of the votes.
4 x 25 = 100
1 x 15 = 25
So Conroy receives 25/100 or 25% of the votes.
If we add these together and Gilda's 5%, we get 50%. Since there are 100% votes overall, we need to do 100 - 50 = 50.
Kyla receives 50% of the votes.
Answer:
Step-by-step explanation:
Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':
Where "O" is the center of dilation at (a,b) and "k" is the scale factor.
In this case you can identify that:
Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:
Vertex D' →
Vertex E' →
Vertex F' →
Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23
Step-by-step explanation:
Formula for margin of error :
, where z* = Critical z-value.
Given: population standard deviation = 11.5 ounces
Sample size = 20
Z value for 90% confidence level = 1.645
margin of error (E) =
Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23