Y = mx+b (slope intercept form). I imagine the point is (2,2) and m = 0. So the answer is y = 2. A sketch would be a horizontal line on the x-y plane going through (2,2).
Answer:
(d) f(x) = -x²
Step-by-step explanation:
For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...
f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)
f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)
Of the offered answer choices, the only one with a vertex at the origin is ...
f(x) = -x² . . . . . a=-1
Answer:
D) 45
Step-by-step explanation:
5 x 3 x 3 = 45
Greater 1 km = 1000 m
so it's greater than 999 m
