Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:
<h3>What is the trigonometric identity using in this problem?</h3>
The identity that relates the sine squared and the cosine squared of the angle, as follows:

In this problem, we have that the sine is given by:

Hence, applying the identity, the cosine is given as follows:






The tangent is given by the sine divided by the cosine, hence:




More can be learned about trigonometric identities at brainly.com/question/24496175
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Answer:
10000
Step-by-step explanation:
5000+100(50)
=10000
Answer:
Range of Function : { - 9, - 5, - 1, 4 }
Step-by-step explanation:
We know that y = 2x - 5 provided the domain ( x - values ) { - 2, 0, 2, 4 }. Let us substitute each element in this set of domain as x in the equation "y = 2x - 5" as to solve for the y - values, otherwise known as the range of the function.
{ - 2, 0, 2, 4 }
y = 2( - 2 ) - 5 = - 9,
y = 2( 0 ) - 5 = - 5,
y = 2( 2 ) - 5 = - 1,
y = 2( 4 ) - 5 = 4
We have the set of y - values as { - 9, - 5, - 1, 4 }. This is the range of our function.