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natulia [17]
3 years ago
14

What is 3x-2y=4 when written in slope intercept form

Mathematics
1 answer:
Verdich [7]3 years ago
7 0

Answer: y = 3/2x - 2

Step-by-step explanation:

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Use the formula for the sum of a geometric series to find the sum or state that the series diverges (enter div for a divergent s
Iteru [2.4K]
This is a geometric series with first term e^3 and common ratio e^-2. The sum of it will be
.. e^3/(1 -e^-2) ≈ 23.229277815766...
5 0
3 years ago
Pls help me with this one, I'll give brainlest :)
rosijanka [135]

Answer:

Step-by-step explanation:

3v + u + 66 = 360

<em>Subtract 66 from 366</em>

3v + u = 294

<em>check images</em>

<em>for more steps</em>

4 0
3 years ago
Piece of wire
Sergeeva-Olga [200]

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combined area of the two figures is a minimum? (Round your answers to two decimal places.)

Step-by-step explanation:

5 0
3 years ago
Which number line represents the solution set for the inequality 3(8 – 4x) &lt; 6(x – 5)?
Marizza181 [45]

The number line which represents the solution set for inequality 3(8-4x)<6(x-5) is (3,inf).

Given an inequality 3(8-4x)<6(x-5).

We have to find the solution set for the given inequality.

<h3>What is inequality?</h3>

A statement of an order relationship greater than, greater than or equal to, less than, or less than or equal to between two numbers or algebraic expressions.

3(8-4x) < 6(x-5).

⇒ 24-12x<6x-30

⇒ 24+30<6x+12x

⇒ 54<18x

⇒ x>54/18

⇒ x>3

Hence, the number line which represents the solution set for inequality 3(8-4x)<6(x-5) is (3,inf).

That is starting from 3 and goes up to infinity.

To learn more about inequality visit:

brainly.com/question/24372553

#SPJ1

7 0
3 years ago
Sqrt45a^5 simplified
Anestetic [448]

\sqrt{45a^5}

[scomposition of 45]

\sqrt{9*5*a^5}

[9 = 3^2, must use this notation (not 3*3)]

\sqrt{3^2*5*a^5}

[We appy one of the proprieties of square roots]

\sqrt{3^2}* \sqrt{5}*\sqrt{a^5}

[now we semplify: we must take out as much as possible all the elements under roots]

[to do that, we must divide the esponent of each element with the index of square roots (2)]

so

\sqrt{3^2}, 2/2 = 1

\sqrt{5}, 1/2 = 0 with 1 of rest

\sqrt{a^5}, 5/2 = 2 with 1 rest

[well, after do that, we can take out the elements under tbhe square roots!]

The quotient of each division is the esponent of the element out of the root

The rest of each division is the esponent of the element under the root

so:

3^{1} (quotient = 1, see the first operation) * \sqrt{5} (rest = 1, see the second operation) * a^{2} (quotient = 2, see the third operation) * \sqrt{a^1} (rest = 1, see the third operation)

The final result is:

3 (=3^1) * a² * √5 * √a

3a²√5a

It's more intuitive and easy, but the explanation (necessary) is very long. If you have other questions, ask me here in the comments! Also sorry for my english, not so good!

8 0
4 years ago
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