-<br> The midpoint of AB = ([?],[ ])<br> M = (x1+x2Yiy2

A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019

kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$6\5=\frac{6}{100}=0.06$

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

$y=14,000*(1-0.06)^x$

$y=14,000*(0.94)^x$

Let us find x by subtracting 2010 from 2019.

$x=2019-2010=9$

Upon substituting x=9 in our function we will get,

$y=14,000*(0.94)^9$

$y=14,000*0.5729948022286167$

$y=8021.927\approx 8022$

Therefore, the population of fish in 2019 will be 8022.

6 0

2 years ago

Help me with this one.......

NemiM [27]

The rachos were sold are 6
because ratio of them at the begining = 3/4
after selling some popcorns, ratio of them still 3/4
they sold 8 popcorns mean 3/4 = ?rachos / 8popcorns sold
the rachos sold = 3*8/4 = 6

4 0

2 years ago

The problem of matching aircraft to passenger demand on each flight leg is called the flight assignment problem in the airline i

Darina [25.2K]

Answer:

Step-by-step explanation:

Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42

Let X be the no of passengers who report

X is N(132, 42)

Or Z is $\frac{x-132}{42}$

a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.

the probability that the demand will exceed the capacity of this airplane

= $P(X>183) = P(Z>1.21) =$

$=0.5-0.3869\\=0.1131$

b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers

= $P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\$

=0.4474+0.3907

=0.8381

c) the probability that the demand for this flight will be less than 100 passengers

$=P(x$

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers

= $P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96$