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icang [17]
3 years ago
9

Triangles DEF and D'E'F' are shown on the coordinate plane below: . . Triangle DEF and triangle D prime E prime F prime with ord

ered pairs at D negative 1, 6, at E 1, 3, at F 6, 3, at D prime 1, negative 6, at E prime negative 1, negative 3, at F prime negative 6, negative 3. . . What rotation was applied to triangle DEF to create triangle D'E'F'?. . A.90° clockwise. . B.180°. . C.None of the above. . D.90° counterclockwise
Mathematics
2 answers:
Brilliant_brown [7]3 years ago
4 0
<span><u><em>The correct answer is:</em></u>
180</span>°<span> rotation.

<u><em>Explanation: </em></u>
<span>Comparing the points D, E and F to D', E' and F', we see that the x- and y-coordinates of each <u>have been negated</u>, but they are still <u>in the same position in the ordered pair. </u>

 <u>A 90</u></span></span><u>°</u><span><span><u> rotation counterclockwise</u> will take coordinates (x, y) and map them to (-y, x), negating the y-coordinate and swapping the x- and y-coordinates.

<u> A 90</u></span></span><u>°</u><span><span><u> rotation clockwise</u> will map coordinates (x, y) to (y, -x), negating the x-coordinate and swapping the x- and y-coordinates.

Performing either of these would leave our image with a coordinate that needs negated, as well as needing to swap the coordinates back around. 

This means we would have to perform <u>the same rotation again</u>; if we began with 90</span></span>°<span><span> clockwise, we would rotate 90 degrees clockwise again; if we began with 90</span></span>°<span><span> counter-clockwise, we would rotate 90 degrees counterclockwise again. Either way this rotates the figure a total of 180</span></span>°<span><span> and gives us the desired coordinates.</span></span>
aleksley [76]3 years ago
4 0

The Real answer is 90 degrees clockwise not 180 degrees, i tried the approved answer above and got it wrong. If you examine the picture it makes more sense than just rotating it 180 degrees, plus the question doesn't specify if it is 180 degrees clockwise, or counterclockwise, so it makes sense for the answer to be: <u><em>90 degrees clockwise!</em></u>

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What is the value of the 11th term in the following geometric sequence? -5, -10, -20, -40
yaroslaw [1]

You are multiplying 2 to each term each time.

-40 is the 4th term

-40 x 2 = -80

-80 x 2 = - 160

-160 x 2 = -320

-320 x 2 = -640

-640 x 2 = -1280

-1280 x 2 = -2560

-2560 x 2 = -5120

-------------------------------------------------------------------------------------------------------------------

-5120 is your 11th term.

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hope this helps

3 0
3 years ago
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Determine which method would be more efficient for solving: Rewriting and using the distributive property or dividing. Solve eac
liq [111]

Answer:

A.  x = 3.03

B.  x = 4/3

Step-by-step explanation:

A.  2000 (x-0.03) = 6000 is quickly simplified byu dividing both sides by 2000:

(x - 0.03) = 3.  Removing the parentheses, we get:  x = -0.03 = 3, or x = 3.03.

B.  The distributive property is the faster method here.  We determine that the LCD is 12 and multiply both sides of this equation 1/4 (4+x) = 4/3 by 12:

3(4 + x) = 16

and then carry out the indicated multiplication:  12 + 3x = 16, or

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7 0
3 years ago
PLEASE HELP!!! THIS IS MY LAST QUESTION!!!! PLEASE!
sladkih [1.3K]

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2, -2, 0

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3 years ago
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What property -3(m + 8) = -3m - 24
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3 years ago
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

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4 years ago
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