Answer:
x = 4/15 and x= 10/3
Step-by-step explanation:
|9x-7|=|6x+3|
There are two solutions, one positive and one negative.
(9x-7)=6x+3 - (9x-7)=6x+3
We will take the positive one first
(9x-7)=6x+3
Subtract 6x from each side
(9x-6x-7)=6x-6x+3
3x -7=3
Add 7 to each side
3x-7+7 = 3+7
3x = 10
Divide by 3x/3 = 10/3
x = 10/3
Now we will take the negative solution
- (9x-7)=6x+3
Distribute the negative sign
-9x+7 = 6x+3
Add 9x to each side
-9x+9x+7 = 6x+9x+3
7 = 15x+3
Subtract 3 from each side
7-3 = 15x +3-3
4 = 15x
Divide by 15 on each side
4/15 =15x/15
4/15 =x
X is the base of the exponent.
For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
