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jek_recluse [69]
3 years ago
10

Is the answer a, b, c, or d.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
4 0
The correct answer is D.

-2 \leq y\ \textless \ 3

The graph shows the set of values that y takes, so you can see that the thick black line goes from -2 to 3 and the black point at -2 represents a closed interval at this point and the empty point at 3 represents an open interval at that point.
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Maggie wants to know how many students in her school enjoy watching sports on TV. She asks all 25 students in her math class and
skelet666 [1.2K]
Your answer would be, <span>No, it is not a valid inference because her classmates do not make up a random sample of the students in the school </span>
5 0
3 years ago
What is the 10th term for sequence 4; 8; 13; 19; 26​
Mariana [72]

Answer:

40

Step-by-step explanation:

3 0
2 years ago
Jemina flips a disc of the type shown below:
LekaFEV [45]

Answer: 1/2


Step-by-step explanation: There are only 2 sides in the disc, so there will be a 1/2 chance of landing in one side, and a 1/2 chance of landing in the other side.

So the answer is 1/2!

Hope this helped!

Plz mark brainliest!


5 0
3 years ago
PLS HELP ASAP.........
Alchen [17]

Answer:

Step-by-step explanation:

Because there is sound and a tune that plays again anytime people are shown having fun at the carnival, the Kit Kat commercial is effective. When the sound is silenced, the commercial's lyrics will come to the viewer's thoughts without any further thought.

4 0
2 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
Read 2 more answers
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