Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
slope intercept form: y=mx+b
y=3x+4
slope is also m
b is the y-intercept
answer:
slope is 3
y-intercept is 4
Answer:
((3 / 14) * 3) / 14 = 9 / 196
Step-by-step explanation:
Reduce 9/196 to lowest terms 9 196 is already in the simplest form. It can be written as 0.045918 in decimal form (rounded to 6 decimal places).
Answer:
2
Step-by-step explanation:
Well you should count with fingers, one finger and one finger, two fingers
Answer: The correct order is D.
