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Kazeer [188]
3 years ago
11

1 ounce = 28.35 grams • 1 gallon = 3.8 liters What is the ratio in ounces per gallon?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0
Hhdg yhftgvg hhuhgyj huh ugh cry Hugh
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Decrease £390 by 10%
Savatey [412]

Answer:

the other guy is correct, i think

Step-by-step explanation:

6 0
2 years ago
Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C.   2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0
3 years ago
Y=x+ 5 <br>y = 6<br>HELP!!<br>Solve this system of equation algerbraically.​
kati45 [8]

Answer:

x = 1

Step-by-step explanation:

plug y = 6 on to the equation y =x + 5

=> 6 = x +5

=> x = 1

5 0
3 years ago
Read 2 more answers
BC = 36; D = 15. What is the value of BD - AC.<br> B<br> A<br> BD - AC =
Snezhnost [94]

Answer:

BD - AC = 0

Step-by-step explanation:

Given that:

BC = 36 , CD = 15 and BD = x

As these are forming right angled triangle,

Using Pythagorean theorem,

(BD)^2+(CD)^2=x^2\\(36)^2+(15)^2 = x^2\\1296 + 225 = x^2\\1521 = x^2\\

Taking square root on both sides

\sqrt{x^2}=\sqrt{1521}\\x=39

As the given shape is rectangular, the sides parallel to each other will have same values.

AB = 15 , AD = 36 and AC = x

(15)^2+(36)^2 = x^2 \\225 + 1296 = x^2 \\1521 = x^2 \\x = 39

Now,

BD - AC = 39 - 39 = 0

Hence,

BD - AC = 0

5 0
3 years ago
Divide the combinations.<br><br> 60C3 / 15C3
Mariulka [41]
I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number


nCr=\frac{n!}{r!(n-r)!}
so
\frac{60C3}{15C3}=
\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }=
( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})=
( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})=
\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}=
\frac{(60!)(12!)}{(57!)(15!)}=
\frac{(60!)}{(57!)(15)(14)(13)}=
\frac{(60)(59)(58)}{(15)(14)(13)}=
\frac{(30)(59)(58)}{(15)(7)(13)}=
\frac{(6)(59)(58)}{(3)(7)(13)}=
\frac{6844}{91}
4 0
4 years ago
Read 2 more answers
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