Prove that the following triangles are similar?
1 answer:
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Answer:
n is a positive integer and here 90, 91, 92, 93, 94 and 95 is 9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
so mathematical induction is prove given below.
Step-by-step explanation:
9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
lets us consider by P (n) for the base case n = 0 then 9⁰ = 1 So P (1) is true
k ≥ 1so consider all integers
1≤l≤ k
There is a need to prove P (k+1)
if k is odd
=
.9.
is 9 so
= 9 +10m
then
= 9 ( 9 + 10m)
=81 + 10 (9m)
so digit is 1 and k +1 is even
So if you subtract the 0 out from the left side, the equation is now 
. Since a x is common in both of the terms on the left side, you can factor it out, now making the equation look like 
. When factoring, each of the separate things (x and (x-3)), must equal zero while the other one doesn't matter. So in order for the equation to be 0, the only potential options for x is 0 and 3. Therefore x=0 and x=3 are the two solutions
We have the equation
Let's complete the square, to do it let's add and subtract 25 on the right side
Now we can have y in function of x
Now we can already identify the vertex because it's in the vertex form:
Where the vertex is
As we can see, h = 5 and k = -2, then the vertex is
Now we can continue and find the focus, the focus is
We have a = 1/20, therefore
The focus is
And the last one, the directrix, it's
Then
Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7