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yarga [219]
2 years ago
11

Simplify the expression, if possible. State the excluded values,if any.

Mathematics
1 answer:
Mrac [35]2 years ago
5 0
5.            5x-5 
.       ------------------
.        10x²-25x+15

We can first factor 10x²-25x+15, it will turn into (2x-3) and (5x-5) 
  (if you need help on factoring, please leave a comment)

So the question will be like:
.            5x-5
.        ---------------                  
.       (2x-3)(5x-5)               The factored answer is the same as the original           .                                         number, so the factor answer can replace it.

We know 5x-5 on the top and 5x-5 on the bottom is the same, so they can cancel out, and it will become:
2x-3=0 

Then solve
2x-3=0 
2x=3
x=2/3

6.

Hope this helps! Please give me the Brainliest answer if you like it! If you have further questions, you can leave a comment or add me as a friend!

(if you need more explanations, please leave a comment)



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vlada-n [284]

Answer:

A. 1/8

Step-by-step explanation:

m = rise/run

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m = (-5- - 4)/(1-9)

m = (-5+4)/(-8)

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5 0
3 years ago
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HELP PLEASE A cylinder and its dimensions are shown. Which equation can be used to find V, the volume of the cylinder in cubic c
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Solve the system: <br> 2x+6y=36<br> x+4y=20
Assoli18 [71]

<u>Let's solve this problem step-by-step</u>

<u>Let's set</u>:

   2x + 6y = 36 -- equation 1

   x + 4y = 20 -- equation 2

(equation 2) * 2

   2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

   2y = 4

   y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

   x + 4(2) = 20

   x = 20 - 8

   x = 12

<u>Thus x = 12 and y = 2</u>

<u>Let's check, by substituting these values</u>

  2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20

<u>Answer: x = 12 and y = 2</u>

Hope that helps!

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2 years ago
I'm answering any 5th grade and below questions​
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Step-by-step explanation:

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3 years ago
Choose the congruence theorem that you would use to prove the triangles congruent.
Elena L [17]

<u><em>Answer:</em></u>

SAS

<u><em>Explanation:</em></u>

<u>Before solving the problem, let's define each of the given theorems:</u>

<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle

<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle

<u>Now, let's check the given triangles:</u>

We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

This means that the two triangles are congruent by <u>SAS</u> theorem

Hope this helps :)

5 0
3 years ago
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