1. 3/4 x 36 = 27
2. 30 x 13/10 = 39
3. 9/8 x 32 = 36
4. 1/2 x 60 = 30
5. 3/4 x 60 = 45
6. 3/10 x 1000 = 300
7. 4/5 x 100 = 80
~Good Luck~!
Bedroom 1 will cost you approx. £24. How I got this? 6 x 4 to find the area.
Bedroom 2 will cost you approx. <span>£31. How I got this? 5 x 6.2 to find the area.
Bedroom 3 will cost you approx. </span><span>£3. How I got this? 2 x 1.5 to find the area.</span>
Answer: OPTION A.
Step-by-step explanation:
Given the following function:
![h(x)=-\frac{1}{4}x^2+\frac{1}{2}x+\frac{1}{2}](https://tex.z-dn.net/?f=h%28x%29%3D-%5Cfrac%7B1%7D%7B4%7Dx%5E2%2B%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B1%7D%7B2%7D)
You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:
![x=\frac{-b}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%7D%7B2a%7D)
In this case:
![a=-\frac{1}{4}\\\\b=\frac{1}{2}](https://tex.z-dn.net/?f=a%3D-%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5Cb%3D%5Cfrac%7B1%7D%7B2%7D)
Then, substituting values, you get:
![x=\frac{-\frac{1}{2}}{(2)(-\frac{1}{4}))}\\\\x=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B%282%29%28-%5Cfrac%7B1%7D%7B4%7D%29%29%7D%5C%5C%5C%5Cx%3D1)
Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>
Your answer to your question is 4.27
Answer:
x = 5 is the right answer.
Step-by-step explanation:
As we know sum of all angles in a triangle is 180°.Therefore in this question we will form an equation.
Sum of all the angles of a triangle = 180
91 + 10x - 4 +8x +3 = 180
90 + 18x = 180
18x + 90 - 90 = 180 - 90
18x = 90
x = 90÷18 = 5
Therefore x = 5 is the right answer.