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PolarNik [594]
3 years ago
14

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

est vacuum chamber you can find is 60 cm in diameter. Part A What magnetic field strength will you need?
Physics
1 answer:
timama [110]3 years ago
6 0

Answer:

The magnetic field strength, B is 1.043 T.

Explanation:

The expression for the magnetic field is as follows as;

B=\frac{mv}{qr}

Here, m is the mass, r is the radius, v is the speed, q is the charge and B is the magnetic field.

According to the given problem, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light.  The largest vacuum chamber you can find is 60 cm in diameter.

v= 10% of the speed of the light

v=\frac{10}{100}\times3\times10^{8}ms^{-1}

v=3\times10^{7}ms^{-1}

r=\frac{Diameter}{2}

r=\frac{60}{2} cm

r=0.30 m

Calculate the magnetic field strength.

B=\frac{mv}{qr}

Put v=3\times10^{7}ms^{-1}, m=1.67\times10^{-27}ms^{-1} kg, q=1.6\times10^{-19}C and r=0.30 m.

B=\frac{(1.67\times10^{-27})(3\times10^{7})}{(1.6\times10^{-19})(0.30)}

B= 1.043 T

Therefore, the magnetic field strength is 1.043 T.  

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A box with a mass of 12.5 kg sits on the floor. how high would you need to lift it for it to have a gpe of 355 j
grandymaker [24]
Gpe=mgh

355=12.5×10×h
h=355/125= 2.84m
3 0
4 years ago
While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential
Maurinko [17]

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

The mass of the lighter construction worker, m₁ = 90 kg

The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.

8 0
3 years ago
Determine the elastic energy U stored in<br> the compressed spring.
hoa [83]

Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

Explanation:

7 0
3 years ago
an object of mass 1 g is hung from a spring and set in oscillatory motion .At t=0 the displacement is 43.75cm and the accelerati
charle [14.2K]

The spring constant is 4.0\cdot 10^{-5} N/m

Explanation:

For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

a=-\omega^2 x

where

a is the acceleration

\omega is the angular frequency

x is the displacement

The angular frequency is defined as

\omega=\sqrt{\frac{k}{m}}

where

k is the spring constant

m is the mass

Substituting the second equation into the first one, we get

a=-\frac{k}{m}x

In this problem we have

m = 1 g = 0.001 kg

And at t=0,

x = 43.75 cm

a = -1.754 cm/s

Therefore, we can re-arrange the equation above to find the spring constant:

k=-\frac{ma}{x}=-\frac{(0.001)(-1.754)}{43.75}=4.0\cdot 10^{-5} N/m

#LearnwithBrainly

6 0
3 years ago
A spacecraft is flying away from the moon toward earth.
Alekssandra [29.7K]

Answer:

it will  decrease

Explanation:

According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.

4 0
3 years ago
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