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vesna_86 [32]
3 years ago
5

While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential

Physics
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

The mass of the lighter construction worker, m₁ = 90 kg

The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.

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The heat generated by a stove element varies directly as the square of the voltage and inversely as the resistance. If the volta
madam [21]

Answer:

The resistance needs to be increased by a factor of 25 to quadruple the amount of heat generated

Explanation:

Let H be the heat generated by the stove element, V its voltage and R its resistance.

So, H ∝ V²/R

H = kV²/R

HR/V² = k

H₁R₁/V₁² = H₂R₂/V₂²

If H₂ = 4H₁ and V₂ = 10V₁

H₁R₁/V₁² = 4H₁R₂/(10V₁)²

H₁R₁/V₁² = 4H₁R₂/100V₁²

R₁ = R₂/25

R₂ = 25R₁

The resistance needs to be increased by a factor of 25 to quadruple the amount of heat generated.

3 0
3 years ago
A 110 kg tackler moving at 2.5m/s meets head on (and holds on to) an 82 kg halfback moving at 5.0m/s. what will be their mutual
Leona [35]

Answer:

0.7 m/s

Explanation:

We can solve the problem by using conservation of momentum.

Before the collision, the momentum of the first tackler is:

p_1 = m_1   v_1 =(110 kg)(2.5 m/s)=275 kg m/s

while the momentum of the second tackler is

p_2 = m_2 v_2 =(82 kg)(-5.0 m/s)=-410 kg m/s

Note that we used a negative sign because the direction of the second tackler is opposite to that of the first tackler.

Therefore, the total momentum before the collision is

p_i = p_1 +p_2 =275 kg m/s -410 kg m/s=-135 kg m/s

Since the total momentum is conserved, this is also equal to the final total momentum :

p_f = -135 kg m/s

Which is also equal to

p_f = (m_1 +m_2 )v_f

since the two tacklers continue their motion together with final velocity vf. Re-arranging the previous equation, we can find the the new velocity of the two tacklers:

v_f = \frac{p_f}{m_1 +m_2}=\frac{-135 kg m/s}{110 kg + 82 kg}=-0.7 m/s

and the negative sign means the direction is the one of the second tackler.

3 0
3 years ago
Read 2 more answers
How the volume of regular solids and of liquids is measured?​
ahrayia [7]

Explanation:

the volume of solids is expressed in cubic measurememts of the length times the width, then times the weight.

5 0
3 years ago
Read 2 more answers
Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho
Evgesh-ka [11]

Answer: t = 0.492τ

Explanation: In a circuit where there is a resistor and a capacitor, the equation for a charging capacitor is given by:

q = q_0(1 - e^{\frac{t}{RC} })

where:

q_0 is the equilibrium charge

q is the charge at time t

RC is time constant also called τ (tau)

For this problem, the circuit is charged to 39%, which means: q = 0.39 q_0

0.39q_0 = q_0 (1 - e^\frac{-t}{RC} )

0.39 = 1 - e^\frac{-t}{RC}

e^\frac{-t}{RC} = 0.61

\frac{-t}{RC} = ln(0.61)

-t = ln(0.61)τ

t = 0.492τ

For the condition to be met it is needed 0.492 time constants must elapse.

7 0
3 years ago
An experiment is being done. Name the independent variable, and the dependent variable for the following question.
Nata [24]

Answer:

Independent variable: Surrounding color

Dependent Variable: Eating Habits

Explanation:

Dependent variables are dependent on Independent variables which means that in this question Eating habits are affected by the Surrounding color.

Hope it Helps!!

3 0
3 years ago
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