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vesna_86 [32]
3 years ago
5

While eating lunch high up in a skyscraper, two construction workers calculate their gravitational potential

Physics
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

The mass of the other worker is 45 kg

Explanation:

The given parameters are;

The gravitational potential energy of one construction worker = The gravitational potential energy of the other construction worker

The mass of the lighter construction worker, m₁ = 90 kg

The height level of the lighter construction worker's location = h₁

The height level of the other construction worker's location = h₂ = 2·h₁

The gravitational potential energy, P.E.,  is given as follows;

P.E. = m·g·h

Where;

m = The mass of the object at height

g = The acceleration due to gravity

h = The height at which is located

Let P.E.₁ represent the gravitational potential energy of one construction worker and let P.E.₂ represent the gravitational potential energy of the other construction worker

We have;

P.E.₁ = P.E.₂

Therefore;

m₁·g·h₁ = m₂·g·h₂

h₂ = 2·h₁

We have;

m₁·g·h₁ = m₂·g·2·h₁

m₁ = 2·m₂

90 kg = 2 × m₂

m₂ = (90 kg)/2 = 45 kg

The mass of the other construction worker is 45 kg.

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Explanation:

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What would it mean if neither the red or blue litmus paper changes colors?
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One baked potato provides an average of 30 mg of vitamin C. If 70 potatoes weigh 20 lb., how many milligrams of vitamin C are pr
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Answer:

105 mg

Explanation:

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So,

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Also,

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Thus,

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5 0
3 years ago
jamal is playing with magnetic toy vehicles. He has two identical magnetic vehicles (purple and green) on different sides of a c
KengaRu [80]

Answer:

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Explanation:

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A weight of 1400 pounds is suspended from two cables as shown in the figure. What is the tension in the left cable? _________ po
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Answer:

Following are the solution to this question:

Explanation:

Law:

\to \theta= 180^{\circ}- 50^{\circ}- 25^{\circ}

      = 180^{\circ}- 75^{\circ}\\\\= 105^{\circ}

\to \frac{T_{L}}{\sin (90+50)}= \frac{T_{R}}{\sin (25+90)}=\frac{1400}{\sin (105)}

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