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mariarad [96]
2 years ago
9

Determine the elastic energy U stored in the compressed spring.

Physics
1 answer:
hoa [83]2 years ago
7 0

Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

Explanation:

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Density is a physical property that relates the mass of a substance to its volume. A. Calculate the density, in g/mL , of a liqu
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Answer:

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C) 0.272 g

Explanation:

Every substance, body or material has mass and volume, however the mass of different substances occupy different volumes.  This is where density D appears as a  physical characteristic property of matter that establishes a relationship between the mass m of a body or substance and the volume V it occupies:

D=\frac{m}{V} (1)

Knowing this, let's begin with the answers:

<h2 /><h2>Answer A:</h2>

Here the mass is m=0.155g and th volume V=0.000235L=0.235mL

Solving (1) with these values:

D=\frac{0.155g}{0.235mL} (2)

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<h2>Answer B:</h2>

In this case the mass of a sample is m=4.71g and its density is D=3.63g/mL.

Isolating V from (1):

V=\frac{m}{D} (4)

V=\frac{4.71g}{3.63g/mL} (5)

V=1.297mL (5)

<h2>Answer C:</h2>

In this case the volume of a sample is V=0.293mL and its density is D=0.930g/mL.

Isolating m from (1):

m=D.V (6)

m=(0.930g/mL)(0.293mL) (7)

m=0.272g (8)

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