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ICE Princess25 [194]
3 years ago
5

Hi!! I need help with this task Can someone help me please..

Mathematics
1 answer:
dsp733 years ago
5 0
The answer you’re looking for is B
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The perimeter of a square is 44 centimeters. what is its area?
aalyn [17]

Answer:

Perimeter = 44cm

we know that square has 4 sides which are same

so perimeter means sum of all 4 sides

4 × s = 44cm

s = 11cm

Each side will be of 11cm.

Now area of square is Square of its side length.

so area = 11 × 11 = 121 cm^2

8 0
2 years ago
If y = x + 5 and y = 11, then x = what?
Anestetic [448]

Answer:

6

Step-by-step explanation:

5 0
2 years ago
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Every workday, Zoe bikes 2.6 miles to work along city streets. On the way back, she likes to take a shortcut through a park, so
snow_lady [41]

Answer:

I'm pretty sure it's 7.1 miles in a week

8 0
3 years ago
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A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random v
Dima020 [189]

Answer: 2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

3/11 because you have 3 labeled 2

6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

2 x 3/11 = 0.5454 = 0.55

3 x 6/11 = 1.63

Then add them all together to find the μ

0.18 + 0.55 + 1.63 = 2.36

Hope that helps, plz put a good rating

4 0
2 years ago
How do i make a table of values for each function rule and then graph the function for these examples:
Sholpan [36]
\bf \begin{array}{ccllll}
y=1.5x-3\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&1.5(-3)-3\\
-2&1.5(-2)-3\\
-1&1.5(-1)-3\\
0&1.5(0)-3\\
1&1.5(1)-3\\
...&...
\end{array}       \bf \begin{array}{ccllll}
y=-x^2+4\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&-(-3)^2+4\\
-2&-(-2)^2+4\\
-1&-(-1)^2+4\\
0&-(0)^2+4\\
1&-(1)^2+4\\
...&...
\end{array}

and so on, and then,  you graph those x,y coordinates
5 0
3 years ago
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