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3 years ago

write the linear equation in slope-intercept form passing through the point with the given slope (1,3) and (-3,-5)

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

Answer:

y = 2x + 1

Step-by-step explanation:

本题已由中国数学会官方解答（现有会员：3人）

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"The graph of F(x), shown below, resembles the graph of G(x) = x2, but it has been changed somewhat. Which of the following coul

SpyIntel [72]

G(x)=x²
The graph has moved to the right 4 units, therefore the new graph will be:
H(x)=(x-4)²

It has also move 4 units up, therefore the new graph will be:
F(x)=(x-4)²+4

Answer:
F(x)=(x-4)²+4

5 0

3 years ago

Read 2 more answers

A refrigerator costs $580 a year to run. A family purchases a new one for $1200 that will save them 22% annually in energy costs

NeTakaya

Answer:

It will take nine years and four months for the refrigerator to pay for itself.

Step-by-step explanation:

The new refrigerator which costs $1200, saves the family 22% annually in energy cost.

Since the old refrigerator costs $580 to run, we want to determine how many years it will take for 22% of $580 per year to make $1200.

22% of $580

= 580 × 0.22

= 127.6

That is, it saved then $127.6 per year.

Now,

$1200/127.6

≈ 9.4

Which means, it will take 9 years and 4 months for the refrigerator to pay for itself.

7 0

3 years ago

The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, & the square of t

never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

$Q=I^2Rt$

$\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega$

So, the new resistance is 4 ohms.

5 0

3 years ago

0.5a − 0.3 = 5 (solve for a)

Alla [95]

0.5a - 0.3 = 5

Add 0.3 to both sides:

0.5a = 5.3

Divide both sides by 0.5:

a = 10.6

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3 years ago

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What is the acceleration due to gravity of a planet where a mass of 45.0 kg has a weight of

AnnZ [28]

Answer:

Normally, Acceleration due to gravity is

$9.8m/s^2\\$

$10m/s^2$

Step-by-step explanation:

From the web

These two laws lead to the most useful form of the formula for calculating acceleration due to gravity: g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance

6 0

3 years ago