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4 years ago

7

Can someone help me? I had the notes in my notebook but I threw it away when it got full, not thinking that I was ever gonna nee

d these notes again.. ;,)

1 answer:

natima [27]4 years ago

7 0

1. The mistake is in the second line (didn't fully distribute)
2. The mistake is in the second line (didn't properly add 4p and 7p)

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In one round robin chess tournament, 36 games were played. How many players entered in the tournament?

ICE Princess25 [194]

$\displaystyle
\binom{n}{2}=36\\\\
\dfrac{n!}{2!(n-2)!}=36\\
\dfrac{n(n-1)}{2}=36\\
n(n-1)=72\\
n^2-n-72=0\\
n^2-9n+8n-72=0\\
n(n-9)+8(n-9)=0\\
(n+8)(n-9)=0\\
n=-8 \vee n=9$

The number of players can't be negative, so there was 9 players.

6 0

4 years ago

in a bag of 20 marbles, 4 are blue. what is the probability that one taken at random will not be blue?

Ber [7]

Your answer is 4/5, which is 80% or 0.8

If there are 20 marbles in total in the bag, and 4 blue ones, that means that the probability of taking a blue one is 4/20.

This means that the probability of not taking a blue one is 1 - 4/20, or 20/20 - 4/20, which equals 16/20 = 4/5

I hope this helps! Let me know if you have any questions :)

6 0

3 years ago

Read 2 more answers

The value of 5 in the number 357.21 is

Mamont248 [21]

Its 50, its in the 10s place

4 0

3 years ago

Use the expression (a+b)(c-d)+9e(a+b)(c−d)+9eleft parenthesis, a, plus, b, right parenthesis, left parenthesis, c, minus, d, rig

jek_recluse [69]

Answer:

Difference: ¨c-d¨ variable: ¨a¨ coefficient: ¨9¨

Step-by-step explanation:

Just trust me bro

8 0

3 years ago

Use the minimum and maximum data entries and the number of classes to find the class width, the lower class limits, and the uppe

deff fn [24]

Answer:

The class width is $C_w \approx 13$

Step-by-step explanation:

From the question we are told that

The upper class limits is $max = 121$

The lower class limits is $min = 14$

The number of classes is $n = 8 \ classes$

The class width is mathematically represented as

$C_w = \frac{max - min}{n }$

substituting values

$C_w = \frac{121 - 14}{8 }$

$C_w = 13.38$

$C_w \approx 13$

Since

5 0

3 years ago