You can solve this by setting up 2 equations and solving quadratically.
perimeter of a rectangle is found by the formula 2*base + 2*height = perimeter.
area is found by base*height=area.
2b+2h = 24 and b*h=27 solving one equation for base or height and substituting in the other equation will give us an equation we can use for this particular problem. solving b*h=27 for b will give us b= 27/h. substituting this into the perimeter equation we get 2(27/h) + 2h = 24. If we use algebra to manipulate the equation we get 24-2h= 2(27/h) so 24-2h = 54/h multiplying both sides by h give (24-2h)h = 54 moving the 24h-2h^2 to the other side gives 0 = 2h^2-24h+54 solving the quadratic for h gives (2h+6)(h+9)=0 so solving for h we get h=6/2 = 3 or h=9 is we use h =9 and plug it into the original equation for 2b+2h=24 then we get 2b+2(9)= 24 so then 2b = 24-18 so b = 6/2 =3. so we get 2(3)+2(9)=24 so 6+18=24 for perimeter and for b*h=27 we get 3*9=27 so the dimensions are 3x9 3 is the shorter side and 9 is the longer side = 3x9
<u>33%</u> of 75 is 25... Hope that helps!!
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>What point is in the circumference of an unit circle?</h3>
<em>Unit</em> circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:
Point A
![d = \sqrt{4^{2}+3^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B4%5E%7B2%7D%2B3%5E%7B2%7D%7D)
d = 5
Point B
![d = \sqrt{\left(\frac{1}{2} \right)^{2}+\left(\frac{1}{5}\right)^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5E%7B2%7D%2B%5Cleft%28%5Cfrac%7B1%7D%7B5%7D%5Cright%29%5E%7B2%7D%20%7D)
d = √29 /10
d ≈ 0.539
Point C
![d = \sqrt{\left(\frac{3}{4} \right)^{2}+\left(\frac{7}{4} \right)^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cleft%28%5Cfrac%7B3%7D%7B4%7D%20%5Cright%29%5E%7B2%7D%2B%5Cleft%28%5Cfrac%7B7%7D%7B4%7D%20%5Cright%29%5E%7B2%7D%7D)
d = √58 /4
d ≈ 1.904
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>Remark</h3>
The statement presents a typing mistake, correct form is shown below:
<em>A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?</em>
To learn more on circles: brainly.com/question/11987349
#SPJ1
$11.00 was the amount for each