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Alekssandra [29.7K]
3 years ago
15

Rita is the manager of the football team, and she has been assigned the task of painting a mascot in the middle of the field. Th

e painting fits neatly in the shape of a square with one side of the painting equal to five yards. The area of the square is given the formula A=s2, where s is the length of a side. What is the area of the painting in square yards?
Mathematics
1 answer:
Alik [6]3 years ago
4 0

Answer:

25 square yards

Step-by-step explanation:

We assume that "fits neatly" means "fills" so that the area of the painting is the same as the area of the square. Put the numbers in the formula and do the arithmetic.

A = (5 yd)² = 5² yd² = 25 yd²

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Answer:

Option A: 1.50x +15

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After 10 rides, the total cost of each option will be the same. This total cost is $30

Step-by-step explanation:

X represents how many rides you take. After 10 rides, the total cost of each option will be the same. To find that, keep plugging in numbers into x until the numbers are the same. This total cost where the numbers are the same is $30.

8 0
3 years ago
Solve the following problem.<br><br> 9/5−4/3=
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Answer = 7/15

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4 0
3 years ago
Ken used 1 3/8 cupe of walnuts and 1 3/4 cups of raid in to make trail mix did he make
blondinia [14]

Answer:

3 1/8

Step-by-step explanation:

Add the 1 3/8 cups of walnuts to the 1 3/4 cups of raisins. You will have to make your denominators the same to add the fraction.

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+1 3/4. 3 x 2 = 6. +1 6/8

_____ 4 x 2 = 8. ______

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4 0
3 years ago
The volume of a cone is 3πx3 cubic units and its height is x units.
GaryK [48]

Answer:

It is given that the volume of a cone = 3 \pi x^{3} cubic units

Volume of cone with radius 'r' and height 'h' = \frac{1}{3} \pi r^{2}h

Equating the given volumes, we get

3 \pi x^{3}=\frac{1}{3} \pi r^{2}h

r^{2} h =3 \times 3 x^{3}

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Therefore, r^{2} x =9 x^{3}

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Therefore, r = 3x

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8 0
3 years ago
Read 2 more answers
2x+7y=1<br> X+5y=2 answer using elimination method
miskamm [114]
\left \{ {{2x+7y=1} \atop {x+5y=2\ \ |*(-2)}} \right. \\\\&#10; \left \{ {{2x+7y=1} \atop {-2x-10y=-4}} \right. \\+----\\elimination\ method\\\\&#10;-3y=-3\ \ \ | divide\ by\ -3\\&#10;y=1\\\\&#10;x=2-5y=2-5=-3\\\\&#10;solution:\\ \left \{ {{y=1} \atop {x=-3}} \right.
5 0
3 years ago
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