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3 years ago

9

Looking for Area of regular figures ? How to Steps would be appreciated :)

1 answer:

8090 [49]3 years ago

7 0

Looking for the area of a regular figure would be taking the longest side and the shortest side and multiply

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Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ag

ivanzaharov [21]

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

$D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

$D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

$D=2((7)-1+(D-16)-1)+1$

$D=2(6+D-15)+1$

$D=2(D-9)+1$

$D=2D-18+1$

$D=17 Years$

Dave is 17 years old

Therefore

Johns age is

$J'=(D-16)$

$J'=17-16$

$J'=1year old$

John is 1 year old

7 0

3 years ago

Suppose there are two circles where the radius of one circle is twice the radius of the other circle. Each circle has an arc whe

Artemon [7]

Answer:

$L=2l$ where $l,L$ denote arc lengths of two circles

Step-by-step explanation:

Let $l,L$ denote arc lengths of two circles, $r,R$ denote corresponding radii and

$\alpha _1\,,\alpha _2$ denote the corresponding central angles.

So,

$l=r\alpha _1$ and $L=R\alpha _2$

This implies $\alpha _1=\frac{l}{r}$ and $\alpha _2=\frac{L}{R}$

As each circle has an arc where the measures of the corresponding central angles are the same, $\alpha _1=\alpha _2$

$\frac{l}{r}=\frac{L}{R}$

As radius of one circle is twice the radius of the other circle,

$R=2r$

$\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l$

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2 years ago

Please HElPPP I AM LITERALLY STUCK

Morgarella [4.7K]

Please see attached photo and give brainliest if you can :) it took me a looong time, hope it helped :)

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3 years ago

98.42 divided by 1.8

igomit [66]

54.67 but if rounded it will be 54.7

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3 years ago

Read 2 more answers

I need help on this one plizz

andrew11 [14]

I'm probably wrong but here you go!

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3 years ago