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Stels [109]
4 years ago
6

Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter t

o draw the scale diagram. If the scale length of the badminton court is 26.8 centimeters and the scale width is 12.2 centimeters, what is the actual area of the court?
Mathematics
1 answer:
docker41 [41]4 years ago
8 0

1m = 100cm

1cm → 0.5m

1cm → 0.5 · 100cm = 50cm

The scale: \dfrac{50}{1}=50

length = 26.8cm · 50 = 1,340cm = 13.40m

width = 12.2cm · 50 = 610cm = 6.10m

The area of the court:

A = 13.40 · 6.10 = 81.74 m²

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Answer:

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Step-by-step explanation:

When we have a function:

f(x) = y

the domain is the set of the possible values of x, and the range is the set of the possible values of y.

In this case we have:

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Let's analyze the possible values of x.

The smallest possible value of x must be larger than 0°, as we are workin with suplementary angles.

Knowing this, we can find the maximum value for y:

0° + y = 180°

y = 180° is the maximum of the range.

Then we have:

0° < x

y < 180°

To find the other extreme, we can use the other relation:

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Then, we can impose that x = y (this value will not be either in the range nor the domain)

if x = y then:

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2*x = 180

x = 90°

This will be the maximum of the domain and the minimum of the range.

Then we have that the domain is:

0° < x <90°

And the range is:

90° < y < 180°.

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3 years ago
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Step-by-step explanation:

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