The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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We want to put b alone on one side of the equation.
If we multiply by 1/2, we get 1/4bh = A/2. Not only did we not remove a variable from the left side, we made it even more complicated.
So the answer is A.
Answer:
idk if this is right or not, but I got africa...
Answer:
x = 8
Step-by-step explanation:
so 
rearrange the formula:
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
Step 2. Add both equations together. You'll get:
, which gives x = -2
Step 3. Replace x = -2 in the first equation and calculate y.
The solution is: x=-2, y=5
