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nika2105 [10]
4 years ago
10

what is 678×789 ? I need help on this problem and I don't feel working it out but if you know that would be great!​

Mathematics
2 answers:
Levart [38]4 years ago
5 0

Answer:

534,942

Step-by-step explanation:

<u>Step 1:  Multiply</u>

678 * 789

(600 * 700) + (600 * 80) + (600 * 9) + (70 * 700) + (70 * 80) + (70 * 9) + (8 * 700) + (8 * 80) + (8 * 9)

420000 + 48000 + 5400 + 49000 + 5600 + 630 + 5600 + 640 + 72

<em>534,942</em>

<em />

Answer:  534,942

Salsk061 [2.6K]4 years ago
3 0

Answer:

534942

Step-by-step explanation:

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Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

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The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

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To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

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3 years ago
Help Its due in 3 mins I will give brainliest
I am Lyosha [343]

Answer:

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Step-by-step explanation:

(9x12)+(6x6)

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Read 2 more answers
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