WILL MARK BRAINLIEST! Please help me. :(
1 answer:
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Answer:
The probability that you will get a sum of 4 before you get a sum of 5 is
Step-by-step explanation:
Given : If you roll two fair dice repeatedly.
To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?
Solution :
When two dice are rolled the outcomes are
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total number of outcomes = 36
Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3
The probability that you will get a sum of 4 before you get a sum of 5 is
Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is
Answer:
B. (see attached)
Step-by-step explanation:
All the answers agree that the function is x² for x < 1. Where they disagree is in the slope and y-intercept of the linear portion for x > 1.
The line has a slope that is less than 1 unit of rise for 1 unit of run, so will not be selections A or C, which have slopes of 3.
The y-intercept is clearly positive if we extend the line to the left until it reaches the y-axis. This eliminates selection D from consideration, leaving only selection B.
Answer: The slope is 5
Step-by-step explanation:
You can calculate the slope of the line with this fomula:
Given the points (2,3) and (1,-2), you can identify that:
Now, the final step is to substitute these values into the formula , getting that the slope of this line is: