March is 8 months away from August and the target amount is $600.
August = $50
September = $50 + (0.2*50)=$60
October = $60 + (0.2*60)=$72
November=$72+(0.2*72)=$86.4
December=$86.4 + (0.2*$86.4)=$103.68
January=$103.68+(0.2*103.68)= $124.416
February=$124.416+(0.2*124.416)=$149.3
March=$149.3 +(0.2*149.4)=$179.2
Total amount = $824.6
Yes, she will have money for the trip
Answer:
14
Step-by-step explanation:
x=4 y=1
Substitute them into the equation 3x-4yy+6
3(4)-4(1)+6
12-4+6
Answer:
70
Step-by-step explanation:
7^2 - ( 6-3^3)
PEMDAS
Parentheses first
7^2 - ( 6-3^3)
The exponent in the parentheses first
7^2 - ( 6-27)
7^2 - ( -21)
Now the exponent
49 - (-21)
Now subtract
49 +21
70
Step-by-step explanation:
Distance = rate × time
If b is the speed of the boat in still water, and c is the speed of the current, then:
60 = (b + c) × 4
35 = (b − c) × 3.5
Simplifying:
15 = b + c
10 = b − c
Add the equations together:
25 = 2b
b = 12.5
Plug into either equation to find c:
c = 2.5
The speed of the boat is 12.5 km/h, and the speed of the current is 2.5 km/h.
