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KatRina [158]
2 years ago
11

H(t)=-10x+6 h(?)=-44

Mathematics
1 answer:
Andreyy892 years ago
5 0

Answer: h(<u>5</u>)=-44

Step-by-step explanation:

Given

h(t)=-10x+6

h(?)=-44

Substitute the [-44] value to the first equation

-44=-10x+6

Subtract 6 on both sides

-44-6=-10x+6-6

-50=-10x

Divide -10 on both sides

-50/-10=-10x/-10

x=5

Hope this helps!! :)

Please let me know if you have any questions

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Arte-miy333 [17]

Answer:

825.663706143591cm

Step-by-step explanation:

80cm × 4 = 320cm

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The radius is 40

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Circumference is πd

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In total

320 + 300 + 80 + 125.663... =

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6 0
2 years ago
- what is the circumference of a circle with radius of 14.6 cm? (Round to the nearest tenth.)
wlad13 [49]

   

c = 2 × 14.6 × π = 29.2 × 3.141592 = 91.7344864 ≈ 91.7

Correct anawer:  B



6 0
3 years ago
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

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\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

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7 0
3 years ago
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astra-53 [7]
Answer:
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Step-by-step explanation:
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3 0
2 years ago
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PLEASE HELP! The table defines a function (x:7,10,13,16) (y:21,30,39,48)
Nataly [62]

Answer:

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6 0
3 years ago
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