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2 years ago

Find 3 solutions that satisfy the equation -5x=10+2y

Mathematics

1 answer:

Dominik [7]2 years ago

3 0

Answer:

(2, -10)

(4, -15)

(6, -20)

Step-by-step explanation:

First you should simplify the equation.

-5x=10+2y

-5x-10=2y

-2.5x-5=y

Then put in any number in for x. since we have a decimal I'll make the numbers I put in even the keep the solution whole numbers.

Putting in 2 gives you -10 so (2, -10) is a solution.

Putting in 4 gives you -15 so (4, -15) is a solution.

Putting in 6 gives you -20 so (6, -20) is a solution.

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The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

Solution:

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

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Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

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