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Alik [6]
2 years ago
15

Find 3 solutions that satisfy the equation -5x=10+2y

Mathematics
1 answer:
Dominik [7]2 years ago
3 0

Answer:

(2, -10)

(4, -15)

(6, -20)

Step-by-step explanation:

First you should simplify the equation.

-5x=<u>10</u>+2y

-5x-10=<u>2y</u>

<u>-2.5x-5=y</u>

Then put in any number in for x. since we have a decimal I'll make the numbers I put in even the keep the solution whole numbers.

<u>Putting in 2 gives you -10 so (2, -10) is a solution.</u>

<u>Putting in 4 gives you -15 so (4, -15) is a solution.</u>

<u>Putting in 6 gives you -20 so (6, -20) is a solution.</u>

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Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit
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Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

Let  

a,b,c be the lengths of the sides of a triangle.  

The area is given by:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

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p=\frac{a+b+c}{2}

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}

d=\sqrt{(-4)^{2}+(0)^{2}}

dAB=4\ units

step 2

Find the distance BC

d=\sqrt{(-2+3)^{2}+(1+2)^{2}}

d=\sqrt{(1)^{2}+(3)^{2}}

dBC=\sqrt{10}\ units

step 3

Find the distance AC

d=\sqrt{(-2-1)^{2}+(1+2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

dBC=\sqrt{18}\ units

step 4

a=AB=4\ units

b=BC=\sqrt{10}\ units

c=AC=\sqrt{18}\ units

Find the half perimeter p

p=\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units

Find the area

A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}

A=\sqrt{5.7(1.7)(2.54)(1.46)}

A=\sqrt{35.93}

A=6\ units^{2}

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3 years ago
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