I believe that the answer is 6. Feel free to check yourself but i think its 6
Answer:
2x^2(3x^2-2x-1)
Step-by-step explanation:
12x^4 - 8x^3 - 4x^2
everything is a multiple of 4 so divide the whole thing by 4
12x^4 - 8x^3 - 4x^2/4= 3x^4-2x^3-1x^2
write it in disturbed form
2(3x^4-2x^3-1x^2)
now if u see we can see that the X will be same, so we also have to factor it out and 2 is the exponent that all can give
2x^2(3x^2-2x-1)
Let
x = first consecutive number
x + 1 = second consecutive number
x + 2 = third consecutive number
The sum of these numbers are 111.
x + x + 1 + x + 2 = 111
3x = 111 - 1 - 2
3x = 108
x = 36
Therefore, the smallest number is 36 because other numbers are 37 and 38.
Then the second term’s denominator is
