3) A cookie recipe calls for 9 cups of flour for 4

Mathematics

1 answer:

baherus [9]3 years ago

8 0

Can I have a cookie????

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Which number line represents the solution to the inequality x - 3 > 2

Ivahew [28]

Answer: x > 5

Step-by-step explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.

Since 3 is being subtracted from x, we add 3 to

both sides of the inequality to get x > 5.

When graphing x > 5, we have an open circle on 5 and the

open circle tells us that 5 is not part of our answer.

Then we draw an arrow going to the right to represent

all possible solutions to this inequality, any number greater than 5.

6 0

3 years ago

3. An airplane flies 105 miles in ½ hour. How far can it fly in 1 ¼ hours at the same rate of speed?

raketka [301]

262.5 miles
explanation 1/4 is half of 1/2 so 52.5 is half of 105 and then 210 for an hour of travel

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4 years ago

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Use parallelogram JKLM to find the length of JK.

shepuryov [24]

Opposite sides are congruent in a parallelogram.

so,

JK will be congruent with ML

and

JM will be congruent with KL

hope this helps

5 0

3 years ago

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What is the answer to this and can you answer this quickly please <br> _ in. = 28 ft 10 in

vaieri [72.5K]

The answer is 250 in

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3 years ago

A hemisphere has an area of 256 pi cm^2. What is its volume?

Amanda [17]

$\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\$

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}$

7 0

3 years ago