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Bad White [126]

2 years ago

12

3) A cookie recipe calls for 9 cups of flour for 4

1 answer:

baherus [9]2 years ago

8 0

Can I have a cookie????

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A drawer contains 4 white socks, 5 black socks, and 3 brown socks. Find the probability that...

IRINA_888 [86]

Answer:

5/12

7/12

125/36 = 3,47%

50/11 = 4,54%

Step-by-step explanation:

Probability a black sock is selected when a person chooses 1 sock = 5/12

Probability a white or brown sock is selected when a person chooses 1 sock =

7/12

Probability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%

Pobability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%

3 0

2 years ago

please factor completely !Thank yoy

Vilka [71]

You can download the app photo math and that will help you

8 0

2 years ago

The cost of the meal was 50 she left a $9 tip what was the percent of the tip

Artemon [7]

18% is the % of the tip

7 0

2 years ago

Read 2 more answers

HELP!! I wasn't in class today and I wasn't able to get the answers to this sheet. Anybody have any idea what the answers are?

dusya [7]

Answer:

idk but you can ask your teacher for help

4 0

2 years ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago