HELP ASAP, WILL MARK BRAINLIEST!!!!

A rectangular prism has side lengths of 4 inches, 6 inches, and 7 inches. If all side lengths are multiplied by 5, what happens

alexandr402 [8]

Most likely your answer would be A

4 0

3 years ago

Read 2 more answers

Simplify:

svetlana [45]

Answer:

−(7p+6)−2(−1−2p) = - 3p - 4

Step-by-step explanation:

−(7p+6)−2(−1−2p) = -7p - 6 + 2 + 4p

= (-7p + 4p) + (2 - 6)

= -(7p - 4p) - (6 - 2)

= - 3p - 4

7 0

2 years ago

Arianna gathered data about the distance of 20 cities from the equator and the average hours of sunlight per day in December for

stich3 [128]

Answer-

A. strong negative correlation.

Solution-

Direction of a relationship

Positive- If one variable increases, the other tends to also increase. If one decreases, the other tends to also. It is represented by positive numbers(i.e 0 to 1).
Negative- If one variable increases, the other tends to decrease, and vice-versa. It is represented by negative numbers(i.e 0 to -1)

Strength of a relationship

Perfect Relationship- When two variables are linearly related, the correlation coefficient is either 1 or -1. They are said to be perfectly linearly related, either positively or negatively.
No relationship- When two variables have no relationship at all, their correlation is 0.

As in this case, correlation coefficient was found to be -0.91, which is negative and close to -1, so it is a strong negative correlation.

5 0

3 years ago

Marla bought seven boxes. A week later half of all her boxes were destroyed in a fire. There are now only 22 boxes left. With ho

Cerrena [4.2K]

22*2=44

44-7=37

Marla started with 37 boxes.

5 0

3 years ago

Someone please help !! I don’t know what I’m doing with this !!

dimulka [17.4K]

Answer:

a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

(f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

__

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

sinh(f(x))' = cosh(f(x))·f'(x)

__

b) After the same pattern as in (a), ...

cosh(f(x))' = sinh(f(x))·f'(x)

__

c) Similarly, ...

tanh(f(x))' = sech(f(x))²·f'(x)

__

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

__

Additional comment on notation

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0

2 years ago