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LiRa [457]
3 years ago
10

Yolanda's club has 35 members.It rules requires that 60% of them must be present to vote.At least how many members must be prese

nt to have a vote?
Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:21 members

Step-by-step explanation:

35 *60% =35 *(60/100)

=21

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Solve a^3=64 pleaseeevjelo
MariettaO [177]

Answer:

a=4

Step-by-step explanation:

  • a^3=64

We can see that 64= 4*4*4= 4^3, replacing 64 with 4^3 in the equation:

  • a^3 = 4^3
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8 0
3 years ago
Read 2 more answers
Add -13/4+2/5 using the number line. select the location on the number line to plot the sum
Ivahew [28]
The answer is if you convert. we cant see the number line so, we cant tell you the second part of the problem.. attach the image please.

ok so convert.. -13/4 becomes -65/20 and 2/5 becomes 8/20, so add that and get -57/20, then simplify how you want to. thats your answer
4 0
4 years ago
The ratio of adults to students on the field trip is 3 to 5. If there are 15 students on the field trip, how many adults are the
Kazeer [188]

Answer:

There are 9 adults

Step-by-step explanation:

3:5 = x:15

3/5 = x/15

3(15) = 5x

5x = 45

x = 9 adults

3:5 = 9:15

4 0
3 years ago
A team had 7 wins and 2 losses. What is the percentage of wins?
Yakvenalex [24]

Answer:

78%

Step-by-step explanation:

Total matches=7+2=9

Total wins=7

Percentage of wins=matches won/total matches * 100

= 7/9*100

=77.8%

≈78%

5 0
3 years ago
Mr. Rijo bought 49 bags of soil one week and 28 bags of soil the next week. Which expression correctly applies the
earnstyle [38]

Answer:

49 + 28 = 7(7 + 4)

Step-by-step explanation:

49 bags of soil one week

28 bags of soil the next week

49 + 28 bags of soil purchased in total

Find the GCF (Greatest Common Factor) of 49 and 28.

49/7 = 7

28/7 = 4 (GCF is 7 since it is the largest number that can divide both 49 and 28 equally)

Factor out the GCF + rewrite division above (optional for visualization)

49/7 = 7 -> 49 = 7 * 7

28/7 = 4 -> 28 = 7 * 4

49 + 28 = 7(7 + 4)

Let me know if you have any questions!

8 0
2 years ago
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