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lubasha [3.4K]
3 years ago
7

Organize the following expressions from greatest to least by number of terms: x + 2xyz 9x2yz 18x2 + 5ab − 6y 4x3 + 3x2 − x − 4

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0
I believe the answer would be 2xyz9x2yz18x2 - 6y4x3 + 5ab - 4. the x canceled itself out. 

Anit [1.1K]3 years ago
3 0

Answer:

The answer is the option C

IV, III,I,II

Step-by-step explanation:

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Find a transformation of sin(x) that gives the following <br><br> a. <br><br> b.
riadik2000 [5.3K]

Answer:

a) f(x) = 3sin(2x - π/2) + 1

b) f(x) = 2sin(2x + π) + 2

Step-by-step explanation:

∵ f(x) = Asin(Bx - C) + D

Where ΙAΙ is the the amplitude , 2π/ΙBΙ is the period , -C/B is the horizontal shift and D is the vertical shift

a) The amplitude is 3

   The period is π

    Shift phase: horizontally π/4 to the right , vertically 1 unit up

b) The amplitude is 2

   The period is π

    Shift phase: horizontally π/2 to the left , vertically 2 unit up

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3 years ago
2x + 3y = 0<br> X + 2y = -1<br> Is this one solution <br> No solution <br> Or infinite solution
Bingel [31]
One Solution at point (3, -2)
7 0
3 years ago
Find a - 2b + 3c diminished by a - 2b - 3c + d.
Rasek [7]

a - 2b + 3c -(a - 2b - 3c + d)

=a - 2b + 3c -a + 2b + 3c - d

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7 0
3 years ago
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3 years ago
A student wanted to find the sum of all the even numbers from 1 to 100. He said:
murzikaleks [220]

Answer:

The statements are incorrect as: The sum of even numbers from 1 to 100(i.e. 2550) is not double\twice of the sum of odd numbers from 1 to 100(i.e. 2500).

Step-by-step explanation:

We know that sum of an Arithmetic Progression(A.P.) is given by:

where 'n' denotes the "number" of digits whose sum is to be determined, 'a' denotes the first digit of the series and '' denote last digit of the series.

Now the sum of even numbers i.e. 2+4+6+8+....+100 is given by the use of sum of the arithmetic progression since the series is an A.P. with a common difference of 2.

image with explanation

Hence, sum of even numbers from 1 to 100 is 2550.

Also the series of odd numbers is an A.P. with a common difference of 2.

sum of odd numbers from 1 to 100 is given by: 1+3+5+....+99

.

Hence, the sum of all the odd numbers from 1 to 100 is 2500.

Clearly the sum of even numbers from 1 to 100(i.e. 2550) is not double of the sum of odd numbers from 1 to 100(i.e. 2500).

Hence the statement is incorrect.

Step-by-step explanation:

3 0
3 years ago
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