Answer:
a. Maximum size of file = 8.003 GB
Explanation:
<u>a. Maximum size of file</u>
= (6 * 2 KB) + (2048 * 2 KB) + (2048 * 2048 * 2 KB)
= 12kb + 4096 Kb + 8388608 kb
= 8392716 kb
8392716/1024 mb = 8196.01 MB
8196.01 /1024 GB= 8.003 GB
<u>b. According to above calculation</u>
For 8 GB 6 direct, 1 single and 1 double indirect block requires
so
for 32 GB
24 direct Block
4 single and 4 double indirect block requires
<span>
A client-server relationship is the basic form of a computer network.
-hope this helps.</span>
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