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3 years ago

6/22 to the nearest whole percent? is?

Mathematics

2 answers:

sashaice [31]3 years ago

5 0

Answer: 27%

Step-by-step explanation:

Given the fraction $\frac{6}{22}$ , you need to divide the numerator by the denominator in order to rewrite it as a decimal number.

$\frac{6}{22}=0.27$

Now, to express it in percentage, the final step is to multiply the decimal number by 100.

Therefore, you get that $\frac{6}{22}$ to the nearest whole percent is:

$(0.27)(100)=27\%$

Rus_ich [418]3 years ago

4 0

1) Divide the numbers

6/22= 0.27 (27 is repeating)

2) Multiply the decimal by 100

0.2727(100)= 27.27

3) Round

27.27 is closer to 27

<u><em>Therefore, 6/22 to the nearest whole number is 27%.</em></u>

Hopefully this helps!

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Sammy bought a car and got a discount of 2/5 off the original price of $30,000. How much did Sammy pay for the car after the dis

SVETLANKA909090 [29]

Answer:

$18000

Step-by-step explanation:

To find the do $30000/5 ( do divide the price into 5 parts)

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3 years ago

Given that events A and B are independent with P(A)=0.24P(A)=0.24 and P(B|A)=0.85P(B∣A)=0.85, determine the value of P(B)P(B), r

NemiM [27]

Answer:

P(B) = 0.85

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

$P(A) = 0.24, P(B|A) = 0.85$

These events are independent.

This means that $P(A \cap B) = P(A)*P(B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(B|A) = \frac{P(A)*P(B)}{P(A)}$

$P(B|A) = P(B)$

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3 years ago

The relationship between a rubber band's length and the weight attached to it is a function. The more weight, the longer the rub

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Answer:

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3 years ago

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

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6 0

4 years ago

Which shows the image of quadrilateral ABCD after the transformation R0, 90°?

avanturin [10]

Answer:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

Step-by-step explanation:

The coordinates of rectangle ABCD are A(-1,0), B(0,-1), C(-2,-3), (-3,-2).

The mapping for a rotation through 90° clockwise about the origin is

$(x,y)\to ( - y,x)$

Therefore:

$A(-1,0)\to A'(0,-1)$

$B(0,-1)\to B'(1,0)$

$C(-2,-3)\to C'(3,-2)$

$D(-3,-2)\to D'(2,-3)$

Therefore the image rectangle has coordinates:

A'(0,-1), B'(1,0) , C'(3,-2), and D'(2,-3)

The first choice is correct.

4 0

3 years ago

Read 2 more answers