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BigorU [14]
3 years ago
12

The total length of the stage is 76 feet. If the trap doors are centered across the stage, what is the distance from the left si

de of the stage to the first trap door?
Please help me step by step :)

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
 subtract the 26 1/2 from 76 and then divide by 2

76-26 1/2 = 49 1/2 / 2 = 24 3/4

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Step-by-step explanation:

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HELP ME PLEASE!
Delicious77 [7]
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides).  If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.

Let's see whether they do.

8^2 + 8^2 = 11^2  ???
 64    + 64 = 121?  NO.  This is not a right triangle.

If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:

8^2 + 8^2 = d^2, where d=hypotenuse.  Then 64+64 = d^2, and 

d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.

11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
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